Let us find out the values:
Let us find out the values:
=
=
=
= = 10
Let us find out the values:
Let us simplify:
Let us simplify:
Let us simplify:
[{2 –1)–1}–1]–1
[{2 –1)–1}–1]–1
= 2
Let us simplify:
Let us simplify:
Let us simplify:
Let us simplify:
Let us arrange in ascending order.
In this type of problems we try to make the powers same by taking LCM of them.
Here, are in the powers .
So, we take LCM of 2, 4 and 3.
4= 22
2= 21
3= 31
LCM= 23 = 6
Now,
Here, all the numbers are having same power.
So, in ascending order we have
Hence, .
Let us arrange in ascending order.
In this type of problems we try to make the powers same by taking LCM of them.
Here, are in the powers .
So, we take LCM of 2, 4 and 3.
4= 22
2= 21
3= 31
LCM= 23 = 6
Now,
Here, all the numbers are having same power.
So, in ascending order we have
Hence, .
Let us arrange in ascending order.
260, 348, 436, 524
We will try to make the powers of the same . We can write
260 = = 3212
348 = = 8112
436 = = 6412
324 = = 912
Now, we can clearly see
So, .
Let us prove
= 1
LHS =
Therefore, LHS = RHS
Hence, proved.
Let us prove
= 1
LHS =
Therefore, LHS = RHS
Hence, proved .
Let us prove
LHS =
=(x0) = 1 = RHS
Therefore, LHS = RHS
Hence, proved .
Let us prove
Therefore, LHS = RHS
Hence, proved.
If x + z = 2y and b2 = ac, then let us show that ay–z bz–x cx–y = 1.
Given that x + z = 2y and b2 = ac
We can write from x + z = 2y
…eq(1)
Now, b2 = ac
Now, we can write as
and …eq(2)
Now, LHS = ay–z bz–x cx–y
= b0 = 1 = RHS
Therefore, LHS = RHS
Hence, proved .
If a = xyp–1, b = xyq–1 and c = xyr–1, then let us show that aq–r br–p cp–q = 1.
Given, a = xyp–1, b = xyq–1 and c = xyr–1
Now, LHS = aq–r br–p cp–q
=
= )
=
=
= x0 × y0 = 1 × 1 = 1 = RHS
Therefore, LHS = RHS
Hence, proved.
If and xyz = 1, then let us show that a + b + c = 0.
Given and xyz = 1
Let
Therefore,
…eq(1)
…eq(2)
…eq(3)
Now, xyz = 1
(from eq(1), eq(2)and eq(3))
We know that if base of the exponents are same then the powers are also equal.
Therefore, a + b + c = 0.
Hence the relation is proved.
If ax = by = cz and abc = 1, then let us show that xy + yz + zx = 0.
Given that : -
ax = by = cz = k and abc = 1
Formula used: - (a1) if then
(b1)
………(i)
……… (ii)
……… (iii)
multiplying (i),(ii)&(iii) we get
using formula (a1)
using formula (b1)
…………..proved
Let us solve:
49x = 73
Given that 49x = 73
Formula used: - (a1) if then a = b
Solving it
We can write
Then ,
Using the formula (a1)
Let us solve:
2x + 2 + 2x–1 = 9
Given that 2x + 2 + 2x–1 = 9
Formula used: - (a1) if then a = b
2x + 2 + 2x–1 = 23 + 1
Using formula (a1)
and
x = 1
Let us solve:
2x + 1 + 2x + 2 = 48.
Given that
Formula used: - (a1) if then a = b
and
Let us solve:
Given that
Formula used: - (a1) if then a = b
(b1)
Let us solve:
Given that
Formula used: - (a1) if then
(b1)
Let us solve:
GIVEN THAT
Formula used: - (a1) if then
(b1)
⇒ 5x + 4 = 9
⇒ x = 1
Let us solve:
62x + 4 = 33x . 2x + 8
Given that 62x + 4 = 33x . 2x + 8
Formula used: - (a1) if then
and
The value of (0.243)0.2 × (10)0.6 is
A. 0.3
B. 3
C. 0.9
D. 9
Formula used: - (a1) if then
(b1)
(0.243)0.2 × (10)0.6
The value of is
A. 1
B. 2
C. 4
D.
Formula used: - (a1) if then
(b1)
= 22 = 4
Hence, option (c) is correct.
If 4x = 83, then the value of x is
A.
B.
C. 3
D. 9
Formula used: - (a1) if then
(b1)
……… (i)
And ) ……(ii)
From (i)(ii)
If then the value of (20)2x is
A.
B. 7
C. 49
D. 1
Formula used: - (a1) if then
(b1)
So,
If 4 × 5x = 500, then the value of xx is
A. 8
B. 1
C. 64
D. 27
Formula used: - (a1) if then
(b1)
According to question
If (27)x = (81)y, then let us write x : y.
Formula used: - (a1) if then
(b1)
(27)x = 33x …… (i)
(81)y = 34y …… (ii)
From (i)&(ii) we get
33x = 34y
3x = 4y
According to question
x:y = 4:3
If (55 + 0.01)2 – (55 –0.01)2 = 5x, then let us calculate the value of x and write it.
Formula used: - (a1) if then
(b1)
(c1)
(d1)
Using formula (c1)&(d1)
Using formula (b1)
from formula (a1)
If 3.27x = 9x + 4, then let us calculate the value of x and write it.
Formula used: - (a1) if then
Using formula (a1)
Let us find out the value of and write it.
Formula used: - (a1) if then
(b1)
Solving the equation
=
Let us write explaining the greater value between and with reason.
Given equation are and
Let as find out the value of
…… (a)
But
…… (b)
Now if we compare with then
From (a) and (b)
Therefore are from comparing the exact value.