Let us express the following into degrees, minutes and seconds.
(i) 832’ (ii) 6312’’
(iii) 375’’ (iv)
(v) 72.04°
(i) 832’
1 degree = 60 minutes
(ii) 6312’’
1 degree = 3600 seconds
⇒ 6312’’ = 1 degree 45 minutes 12 seconds
(iii) 375’’
1 degree = 3600 seconds
⇒ 375’’ = 6 minutes 15 seconds
Let us determine the circular values of the followings
(i) 60° (ii) 135°
(ii) -150° (iv) 72°
(v) 22°30’ (vi) -62°30’
(vii) 52°52’30’’
(i) 60°
∵ 180° = π
(ii) 135°
∵ 180° = π
(ii) -150°
∵ 180° = π
(iv) 72°
∵ 180° = π
(v) 22°30’
⇒ 20° + 30’
∵ 180° = π
(vi) -62°30’
⇒ -60° - 30’
(vii) 52°52’30’’
⇒ 52° + 52’ + 30’’
∵ 180° = π
In ΔABC, AC=BC and BC is extended upto the point D. If ∠ACD=144°, then let us determine the circular value of each of the angles of ΔABC.
∠ACD = 144°
∵ DCB is straight line, ∠DCB = 180°
⇒ ∠ACB = 180° - 144° = 36°
∵ AC=BC, by opposite angle property
⇒ ∠CAB = ∠CBA = x
By Angle sum Property
⇒ ∠CAB + ∠CBA + ∠ACB = 180°
⇒ 2x + 36° = 180°
⇒ x = 72°
⇒ ∠CAB = ∠CBA = 72° and ∠ACB = 36°
And ∠ACB = 36°
If the difference of two acute angles of a right-angled triangle is , then let us write the sexagesimal values of two angles.
let the two angles be x and y.
∵ it is a right-angled triangle
…[1]
Also, by question
…[2]
Adding eq. [1] and eq. [2]
⇒
…[3]
By eq. [1] and eq. [3]
Converting x to sexagesimal angle
⇒
⇒ x° = 81°
∵ y° = 90° – x°
⇒ y° = 9°
The measure of one angle of a triangle is 65° and other angle is ; let us write the sexagesimal value and circular value of third angle.
converting to sexagesimal
= 15°
Let c be the third angle
∵ sum of angles of a triangle = 180°
⇒ 65° + 15° + c = 180°
⇒ c = 100°
Circular value of c
If the sum of two angles is 135° and their difference is ; then let us determine the sexagesimal value and circular value of two angles.
converting into sexagesimal value
⇒ 15°
Let the two angles be x and y.
x + y = 135° …[1]
x - y = 15° …[2]
adding eq. [1] and eq. [2]
⇒ 2x = 150°
⇒ x = 75° …[3]
By [1] and [3]
y = 60°
converting x to circular
converting y to circular
If the ratio of three angles of a triangle is 2:3:4, then let us determine the circular value of the greatest angle.
let the angles be 2x, 3x, 4x
∵ sum of angles of a triangle = 180°
⇒ 2x + 3x + 4x = 180°
⇒ 9x = 180°
⇒ x = 20°
Angles of the triangle
2x = 40°
3x = 60°
4x = 80°
Circular value of 80°
The length of a radius of a circle is 28 cm. Let us determine the circular value of angle subtended by an arc of 5.5 cm length at the centre of this circle.
let θ be the angle subtended by the arc.
length of arc = rθ
⇒ 28×θ = 5.5
The ratio of two angles subtended by two arcs of unequal lengths at the centre is 5:2 and if the sexagesimal value of the second angle is 30°. Then let us determine the sexagesimal value and the circular value of the first angle.
let the length of arcs be 5x and 2x
Let r be the radius of the circle
…[1]
Let θ be the angle subtended by the arc of length 5x.
…[2]
By dividing eq. [1] and eq. [2]
⇒ θ = 75°
A rotating ray makes an angle π. Let us write by calculating, in which direction the ray has completely rotate and there after what more angle it has produced.
angle of the ray =
The negative sign shows that ray has rotated clockwise.
Adding multiples of 2π
∵ it is greater than , so it is in 2nd quadrant.
I have drawn an isosceles triangle ABC whose included angle of two equal sides is ∠ABC=45°; the bisector of ∠ABC intersects the side AC at the point D let us determine the circular values of ∠ABD, ∠BAD, ∠CBD and ∠BCD.
∠ABC = 45°
∵ BD is the angle bisector of ∠ABC
∠BAD + ∠ABC+ ∠BCD = π
∵ ABC is an isosceles triangle
⇒ ∠BAD = ∠BCD = x
The base BC of the equilateral triangle ABC is extended upto the point E so that CE=BC. By joining A,E, let us determine the circular values of the angles of ΔABC
∠ABC = ∠BAC = ∠BCA = 60°
∠ACE + ∠ACB = 180°
⇒ ∠ACE = 180° - 60°
⇒ ∠ACE = 120°
∵ BC = CE and BC = AC
⇒ AC = AE
⇒ ∠CAE = ∠AEC = x
∠CAE + ∠AEC + ∠ACE = 180°
⇒ 2x + 120° = 180°
⇒ x = 30°
And ∠ACE = 120°
If the measures of three angles of quadrilateral are and 90° respectively, then let us determine and write the sexagesimal and circular values of fourth angle.
sum of angles of quadrilateral = 2π
Let the fourth angle be x
⇒ x = 60°
The end point of the minute hand of a clock rotates in 1 hour
A. radian
B. radian
C. π radian
D. 2π radian
angle of complete circle = 2π
Minute hand completes 1 circle in an hour.
radian equals to
A. 60°
B. 45°
C. 90°
D. 30°
⇒ 30°
The circular value of each internal angle of a regular hexagon is
A.
B.
C.
D.
Sum of internal angle of a polygon = 180(n-2)
⇒ internal angle of a regular polygon=
For hexagon n = 6
⇒ 120°
The measurement of Θ in the relations to S=rΘ is determined by
A. sexagesimal system
B. circular system
C. Those two methods
D. None of these
Circumference of a circle is 2πr
Where 2π is the angle subtended in circular system and r is the radius.
In cyclic quardrilateral ABCD, if ∠a=120°, then the circular of ∠C is
A.
B.
C.
D.
The sum of opposite angle in a cyclic quadrilateral = π
Converting 120° to cyclic
Let us write whether the following statements are true or false:
(i) The angle, formed by rotating a ray centering its end point in anticlockwise direction is positive.
(ii) The angle, formed for completely rotating a ray twice by centering its end point is 720°
(i) True,
Positive angles are made by rotating anti-clockwise.
(ii) True,
On one rotation angle is 360°
∴ 360° × 2 = 720°
Let us fill in the blanks:
(i) π radian is a ______angle.
(ii) In sexagesimal system 1 radian equals to ______(approx)
(iii) The circular value of the supplementary angle of the measure is_____
(i) circular
Radian are denotation for circular angles.
(ii) 57.29
=57.29
(iii) 0
Sum of supplementary angles is π
If the value of an angle in degree is D and in radian is R; then let us determine the value of
Let us write the value of complementary angle of the measure 63°35’15’’
63° + 35’ + 15’’
If the measures of two angles of a triangle are 65°56’55’’ and 64°3’5’’, then let us determine the circular value of third angle.
65°56’55’’
In radians
= 1.064
Angle 2
64°3’5’’
In radians
= 1.130
Third angle
x = π – 1.130 – 1.064
⇒ x = 0.9476
In a circle, if an arc of 220 cm. length subtends an angle of measure 63° at the centre, then let us determine the radius of the circle.
converting 63° to radians
Taking
Let the radius be r.
⇒ r = 200 cm
Let us write the circular value of an angle formed by the end point of hour hand of a clock in 1 hour rotation.
In one complete circle of 12 hours
It completes 2π angle
⇒ In 1 hour, it’ll complete