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Hydrogen

Class 11th Chemistry NCERT Exemplar Solution
Multiple Choice Questions I
  1. Hydrogen resembles halogens in many respects for which several factors are responsible. Of…
  2. Why does H+ ion always get associated with other atoms or molecules?…
  3. Metal hydrides are ionic, covalent or molecular in nature. Among LiH, NaH, KH, RbH, CsH,…
  4. Which of the following hydrides is electron-precise hydride?
  5. Radioactive elements emit α, β and γ rays and are characterised by their halflives. The…
  6. Consider the reactions(A) H2O2 + 2HI → I2 + 2H2O(B) HOCl + H2O2→ H3 O+ + Cl- + O2Which of…
  7. The oxide that gives H2O2 on treatment with dilute H2SO4 is —
  8. Which of the following equations depict the oxidising nature of H2 O2?…
  9. Which of the following equation depicts reducing nature of H2O2?
  10. Hydrogen peroxide is _________.
  11. Which of the following reactions increases production of dihydrogen from synthesis gas?…
  12. When sodium peroxide is treated with dilute sulphuric acid, we get ______.…
  13. Hydrogen peroxide is obtained by the electrolysis of ______.
  14. Which of the following reactions is an example of use of water gas in the synthesis of…
  15. Which of the following ions will cause hardness in water sample?
  16. Which of the following compounds is used for water softening?
  17. Elements of which of the following group(s) of periodic table do not form hydrides.…
  18. Only one element of ________ forms hydride.
Multiple Choice Questions Ii
  1. Which of the following statements are not true for hydrogen?
  2. Dihydrogen can be prepared on commercial scale by different methods. In its preparation by…
  3. Which of the following statement(s) is/are correct in the case of heavy water?…
  4. Which of the following statements about hydrogen are correct?
  5. Some of the properties of water are described below. Which of them is/are not correct?…
  6. Hardness of water may be temporary or permanent. Permanent hardness is due to the presence…
  7. Which of the following statements is correct?
  8. Which of the following statements is correct?
  9. Which of the following statements is correct?
Short Answer
  1. How can production of hydrogen from water gas be increased by using water gas shift…
  2. What are metallic/interstitial hydrides? How do they differ from molecular hydrides?…
  3. Name the classes of hydrides to which H2O, B2 H6 and NaH belong.
  4. If same mass of liquid water and a piece of ice is taken, then why is the density of ice…
  5. Complete the following equations:(i) PbS (s) + H2O2 (aq) →(ii) CO (g) + 2H2 (g) →…
  6. Give reasons:(i) Lakes freeze from top towards bottom.(ii) Ice floats on water.…
  7. What do you understand by the term ‘auto protolysis of water’ ? What is its significance?…
  8. Discuss briefly de-mineralisation of water by ion exchange resin.…
  9. Molecular hydrides are classified as electron deficient, electron precise and electron…
  10. How is heavy water prepared? Compare its physical properties with those of ordinary water.…
  11. Write one chemical reaction for the preparation of D2O2
  12. Calculate the strength of 5 volume H2O2 solution.
  13. (i) Draw the gas phase and solid phase structure of H2O2.(ii) H2O2 is a better oxidising…
  14. Melting point, enthalpy of vapourisation and viscosity data of H2O and D2O is given below…
  15. Dihydrogen reacts with dioxygen (O2) to form water. Write the name and formula of the…
  16. Explain why HCl is a gas and HF is a liquid.
  17. When the first element of the periodic table is treated with dioxygen, it gives a compound…
  18. Rohan heard that instructions were given to the laboratory attendent to store a particular…
  19. Give reasons why hydrogen resembles alkali metals?
  20. Hydrogen generally forms covalent compounds. Give reason.
  21. Why is the Ionisation enthalpy of hydrogen higher than that of sodium?…
  22. Basic principle of hydrogen economy is transportation and storage of energy in the form of…
  23. What is the importance of heavy water?
  24. Write the Lewis structure of hydrogen peroxide.
  25. An acidic solution of hydrogen peroxide behaves as an oxidising as well as reducing agent.…
  26. With the help of suitable examples, explain the property of H2O2 that is responsible for…
  27. Why is water molecule polar?
  28. Why does water show high boiling point as compared to hydrogen sulphide? Give reasons for…
  29. Why can dilute solutions of hydrogen peroxide not be concentrated by heating. How can a…
  30. Why is hydrogen peroxide stored in wax lined bottles?
  31. Why does hard water not form lather with soap?
  32. Phosphoric acid is preferred over sulphuric acid in preparing hydrogen peroxide from…
  33. How will you account for 104.5° bond angle in water?
  34. Write redox reaction between fluorine and water.
  35. Write two reactions to explain amphoteric nature of water.
Matching Type
  1. Correlate the items listed in Column I with those listed in Column II. Find out as many…
  2. Match Column I with Column II for the given properties/applications mentioned therein.…
  3. Match the terms in Column I with the relevant item in Column II.
  4. Match the items in Column I with the relevant item in Column II.
Assertion And Reason
  1. Assertion (A) : Permanent hardness of water is removed by treatment with washing…
  2. Assertion (A) : Some metals like platinum and palladium, can be used as storage media for…
Long Answer
  1. Atomic hydrogen combines with almost all elements but molecular hydrogen does not. Explain…
  2. How can D2O be prepared from water? Mention the physical properties in which D2O differs…
  3. How will you concentrate H2O2? Show differences between structures of H2O2 and H2O by…
  4. (i) Give a method for the manufacture of hydrogen peroxide and explain the reactions…
  5. What mass of hydrogen peroxide will be present in 2 litres of a 5 molar solution?…
  6. A colourless liquid ‘A’ contains H and O elements only. It decomposes slowly on exposure…
  7. An ionic hydride of an alkali metal has significant covalent character and is almost…
  8. Sodium forms a crystalline ionic solid with dihydrogen. The solid is non-volatile and non-…

Multiple Choice Questions I
Question 1.

Hydrogen resembles halogens in many respects for which several factors are responsible. Of the following factors which one is most important in this respect?
A. Its tendency to lose an electron to form a cation.

B. Its tendency to gain a single electron in its valence shell to attain stable electronic configuration.

C. Its low negative electron gain enthalpy value.

D. Its small size.


Answer:

Hydrogen is said to be an analogous element when its position in the periodic table is considered. This is because it shares its properties both with alkali metals as well as with halogens in the field of sharing or gaining electrons or in other words it has its electronic configuration similar to these. That is why its position in the periodic table is not justified.

Hydrogen (1s1) shares the similar electronic configuration with halogens where both of them require to gain only one electron to obtain the stable state configuration. Eg:


F : 1s 2 2s 2 2p 5


Cl : 1s 2 2s 3 2p 6 3s 2 3p 5


So, we can see that according to this electronic configuration, both hydrogen and halogens require to gain only one electron to acquire the stable duplet(for hydrogen) and octet(for halogens) states or a uni-negative ion.


Also the electronic configuration of hydrogen (1s1) is similar to that of alkali metals (ns1) which shows that only one electron is present in their valence shell. So if they lose that single electron, a uni-positive ion would be formed.


Also, the size of a halogen atom does not remain the same all throughout the periodic table. As we go down a group, in a periodic table, more number of electrons are added to the last shell. Thus the nuclear charge cannot reach to the last shells due to which, atomic radius increases.


Question 2.

Why does H+ ion always get associated with other atoms or molecules?
A. Ionisation enthalpy of hydrogen resembles that of alkali metals.

B. Its reactivity is similar to halogens.

C. It resembles both alkali metals and halogens.

D. Loss of an electron from hydrogen atom results in a nucleus of very small size as compared to other atoms or ions. Due to small size it cannot exist free.


Answer:

The reason why any atom or molecule is formed is because the ionic forms cannot remain stable.

When H+ ion is formed, the size of the ion is very small (near about 10-3 pm. The normal atomic and ionic sizes vary from 50 to 230pm. Due to which, it cannot exist freely and it has to be always associated with other atoms or molecules to get stability.


Question 3.

Metal hydrides are ionic, covalent or molecular in nature. Among LiH, NaH, KH, RbH, CsH, the correct order of increasing ionic character is
A. LiH > NaH > CsH > KH>RbH

B. LiH < NaH < KH < RbH < CsH

C. RbH > CsH > NaH > KH > LiH

D. NaH > CsH > RbH > LiH > KH


Answer:

When we go down the Group 1 or the alkali metals group, the elements we observe in order are Li, Na, K, Rb, Cs. As we go down the group, metallic character increases.

Metallic character of something can be expressed as the reluctance to lose electrons. A molecule is said to be more metallic than the other if it loses an electron more easily than the other.


Now, an atom will lose an electron more easily if the nuclear attraction on the electrons of valence shells would be as low as possible to facilitate the loss.


As we go down a group in a periodic table, electrons get added to the last shells. As a result of which the elements which are situated at the bottom of a group do not feel the nuclear attraction which the elements at the top of the group feel. This is because in the elements at the bottom of a group, we see that the valence electrons are very far from the nucleus, due to which the nuclear attraction that these electrons receive is quite negligible. So, these electrons can be removed very easily and the formation of cations is preferred. Therefore, these metals are said to be more metallic than the ones at the top of the group.


So the metallic order is as follows:-


LiH < NaH < KH < RbH < CsH


Question 4.

Which of the following hydrides is electron-precise hydride?
A. B2H6

B. NH3

C. H2O

D. CH4


Answer:

An electron-precise hydride is a type of hydride which has the exact number of electrons required to form normal covalent bonds, no excess no deficient. These are formed generally by group 14 elements like Si and C which have 4 valence electrons.

Eg. CH4 , SiH4, etc.


B2H6 is an electron deficient hydride. These have an incomplete octet. They are formed generally by the group 13 elements like B, Al, etc.


NH3, H2O are examples of electron rich hydrides. These contain excess number of electrons on the central atom called lone pairs. These are formed by group 15,16,17 elements like N, O, F, etc.



Structure of CH4



Structures of NH3 and H2O



Structure of B2H6


Question 5.

Radioactive elements emit α, β and γ rays and are characterised by their halflives. The radioactive isotope of hydrogen is
A. Protium

B. Deuterium

C. Tritium

D. Hydronium


Answer:

Hydrogen has three isotopes – Protium (1H1), Deuterium (2H1), Tritium (3H1). The number of neutrons is the reason why these isotopes differ from each other in spite of having the same atomic number.

Among these isotopes, the only tritium is radioactive isotope and it emits low energy β particles as it has more number of neutrons.


Question 6.

Consider the reactions

(A) H2O2 + 2HI → I2 + 2H2O

(B) HOCl + H2O2→ H3 O+ + Cl- + O2

Which of the following statements is correct about H2O2 with reference to these reactions? Hydrogen perioxide is _______

A. an oxidising agent in both (A) and (B)

B. an oxidising agent in (A) and reducing agent in (B)

C. a reducing agent in (A) and oxidising agent in (B)

D. a reducing agent in both (A) and (B)


Answer:

An oxidising agent is one which oxidises(oxidation number increases) others and itself gets reduced. Whereas a reducing agent reduces (oxidation number decreases) others and itself gets oxidised.


So, we can see that H2O2 acts as an oxidising agent in (A) as it increases the oxidation number of I- in HI from -1 to 0 in I2.


Similarly, H2O2 acts as a reducing agent in (B) as it decreases the oxidation number of Cl+ in HOCl from +1 to -1 in Cl-.


Question 7.

The oxide that gives H2O2 on treatment with dilute H2SO4 is —
A. PbO2

B. BaO2 .8H2O + O2

C. MnO2

D. TiO2


Answer:

Barium peroxide (BaO2) as we can get from its name, has a per-oxy linkage in it. Due to which its treatment with H2SO4 gives H2O2 . Whereas, the other oxides don’t have the per-oxy linkage due to which hydrogen peroxide cannot be produced.



Whereas, all the other oxides give only water instead of hydrogen peroxide due to the absence of the per-oxy linkage in them.


Question 8.

Which of the following equations depict the oxidising nature of H2 O2?
A. 2[Fe(CN)6]4 + 2H+ + H2O2→ 2[Fe(CN)6]3- + 2H2O

B. I2 + H2 O2 +2OH-→ 2I- + 2H2O + O2

C. Mn2+ + H2O2→ Mn-4 + 2OH-

D. KIO4 + H2O2→ KIO3 + H2O + O2


Answer:

In the reaction where ferrocyanide ion reacts with hydrogen peroxide, the oxidation state on ferrocyanide ion is +2 and it increases to +3 in ferricyanide ion in the product. So, here hydrogen peroxide acts as an oxidising agent.


Question 9.

Which of the following equation depicts reducing nature of H2O2?
A. 2[Fe(CN)6]4+ + 2H+ + H2O2→ 2[Fe(CN)6]3- + 2H2O

B. I2 + H2O2→ Mn4+ + 2OH-

C. Mn2+ + H2O2→ Mn4+ + 2OH-

D. PbS + 4H2O2→ PbSO4 + 4H2O


Answer:

Note:- The given reaction is not possible. The actual reaction could have been


In this case, I2 have oxidation number of 0 which reduces to -1 in I-.



This reaction depicts the reducing nature of H2O2.


Question 10.

Hydrogen peroxide is _________.
A. an oxidising agent

B. a reducing agent

C. both an oxidising and a reducing agent

D. neither oxidising nor reducing agent


Answer:

The oxidising state of the oxygen atom on H2O2 is -1 which is an intermediate state. It means that it can either reduce itself to H2O where oxidation state of O is -2 or it can oxidise itself to O2, where the oxidation state of O is 0.

In the first case, H2O2 acts as an oxidising agent and in the second case, it acts as a reducing agent.



Question 11.

Which of the following reactions increases production of dihydrogen from synthesis gas?
A. CH4 (g) + H2O (g) → CO(g) + 3H2 (g)

B. C (s) + H2O (g) → CO (g) + H2 (g)

C. C2 H6 + 2H2O → 2CO + 5H2

D. CO(g) + H2O(g) → CO2(g) + H2(g)


Answer:

The water shift gas reaction is used in the formation of synthesis gas (hydrogen and carbon monoxide or carbon dioxide mixture. Here CO is converted to CO2 and H2 is also obtained from water.


Question 12.

When sodium peroxide is treated with dilute sulphuric acid, we get ______.
A. sodium sulphate and water

B. sodium sulphate and oxygen

C. sodium sulphate, hydrogen and oxygen

D. sodium sulphate and hydrogen peroxide


Answer:

From the name itself, we get to know that sodium peroxide has a per-oxy linkage in it due to which the formation of hydrogen peroxide is always preferred. So, when it reacts with dilute sulphuric acid, we get hydrogen peroxide along with sodium sulphate.



Peroxide linkage in Sodium peroxide


Question 13.

Hydrogen peroxide is obtained by the electrolysis of ______.
A. water

B. sulphuric acid

C. hydrochloric acid

D. fused sodium peroxide


Answer:

From the electrolysis of sulphuric acid (H2SO4), we obtain hydrogen peroxide. We can observe it from the following reactions:


Question 14.

Which of the following reactions is an example of use of water gas in the synthesis of other compounds?
A. CH4 (g) + H2O (g) → CO (g) + H2 (g)

B. CO (g) + H2O (g) → CO2 (g) + H2(g)

C. Cn (g) + 2H2 (g) → nCO + (2n+1) H2

D. CO (g) + 2H2 (g) → CH3OH (l)


Answer:

Water-gas is nothing but a mixture of carbon monoxide (CO) and hydrogen (H2) gases.

Here, in the reaction, water gas is used in the synthesis of methanol (CH3OH).



Question 15.

Which of the following ions will cause hardness in water sample?
A. Ca2+

B. Na+

C. Cl-

D. K+


Answer:

Permanent hardness in water is caused due to the presence of soluble salts of magnesium and calcium in the form of chlorides or sulphates in water. So Ca2+ will cause hardness in water sample.


Question 16.

Which of the following compounds is used for water softening?
A. Ca3 (PO4)2

B. Na3PO4

C. Na6P6O18

D. Na2HPO4


Answer:

Permanent hardness cannot be removed only by simple boiling. One method of removing permanent harness is by Calgon’s method.

Here, calgon, which is sodium hexametaphosphate(Na6P6O18), when added to hard water following reactions take place :



Question 17.

Elements of which of the following group(s) of periodic table do not form hydrides.
A. Groups 7, 8, 9

B. Group 13

C. Groups 15, 16, 17

D. Group 14


Answer:

When the metals of group 7,8,9 react with Hydrogen, they accept the only negative electron of H atom and the metal ion becomes negatively charged and a ligand is formed in this way.

If the opposite would have occurred, like if the metal lost an electron and became positively charged then the compound formed with hydrogen would be known as a hydride.


This trait seen is known as hydride gap.


Question 18.

Only one element of ________ forms hydride.
A. group 6

B. group 7

C. group 8

D. group 9


Answer:

We know metals of group 7,8,9 cannot form hydrides. This is because these metals accept the only negative electron of H atom and the metal ion becomes negatively charged and a ligand is formed in this way.

If the opposite would have occurred, like if the metal lost an electron and became positively charged then the compound formed with hydrogen would be known as a hydride.


This trait seen is known as hydride gap.


So, only group 6 elements form hydrides.



Multiple Choice Questions Ii
Question 1.

Which of the following statements are not true for hydrogen?
A. It exists as diatomic molecule.

B. It has one electron in the outermost shell.

C. It can lose an electron to form a cation which can freely exist

D. It forms a large number of ionic compounds by losing an electron.


Answer:

When a hydrogen atom loses an electron, it forms a cation H+. But it is not at all stable to exist freely. The reason why any atom or molecule is formed is because the ionic forms cannot remain stable.

When H+ ion is formed, the size of the ion is very small (near about 10-3 pm. The normal atomic and ionic sizes vary from 50 to 230pm. Due to which, it cannot exist freely and it has to be always associated with other atoms or molecules to get stability.


Hydrogen exists as a diatomic molecule like H2 and has only one electron in the valance shell.


Question 2.

Dihydrogen can be prepared on commercial scale by different methods. In its preparation by the action of steam on hydrocarbons, a mixture of CO and H2 gas is formed. It is known as ____________.
A. Water gas

B. Syngas

C. Producer gas

(d) Industrial gas


Answer:

Water gas is nothing but a mixture of carbon monoxide (CO) and hydrogen (H2) gases.

The water shift gas reaction is used in the formation of synthesis gas (hydrogen and carbon monoxide or carbon dioxide mixture. Here CO is converted to CO2 and H2 is also obtained from water. The production of dihydrogen can be increased by reacting carbon monoxide of syngas mixtures with steam and using iron chromate as a catalyst.


Question 3.

Which of the following statement(s) is/are correct in the case of heavy water?
A. Heavy water is used as a moderator in nuclear reactor.

B. Heavy water is more effective as solvent than ordinary water.

C. Heavy water is more associated than ordinary water.

D. Heavy water has lower boiling point than ordinary water.


Answer:

Heavy water D2O is used as a moderator in nuclear reactors and in exchange reactions for the study of reaction mechanisms.

Also there is stronger hydrogen bonding in heavy water than in ordinary water due to which it is more associated.


Question 4.

Which of the following statements about hydrogen are correct?
A. Hydrogen has three isotopes of which protium is the most common.

B. Hydrogen never acts as cation in ionic salts.

C. Hydrogen ion, H+ , exists freely in solution.

D. Dihydrogen does not act as a reducing agent.


Answer:

Hydrogen has three isotopes – Protium (1H1), Deuterium (2H1), Tritium (3H1). The number of neutrons is the reason why these isotopes differ from each other in spite of having the same atomic number.

Ordinary hydrogen, protium has no neutrons and thus the predominant form is protium.


When a hydrogen atom loses an electron, it forms a cation H+. But it is not at all stable to exist freely. The reason why any atom or molecule is formed is because the ionic forms cannot remain stable.


When H+ ion is formed, the size of the ion is very small (near about 10-3 pm. The normal atomic and ionic sizes vary from 50 to 230pm. Due to which, it cannot exist freely and it has to be always associated with other atoms or molecules to get stability. So it never acts as cation in ionic salt.


Question 5.

Some of the properties of water are described below. Which of them is/are not correct?
A. Water is known to be a universal solvent.

B. Hydrogen bonding is present to a large extent in liquid water.

C. There is no hydrogen bonding in the frozen state of water.

D. Frozen water is heavier than liquid water.


Answer:

In water due to the electronegative oxygen atom, we can see hydrogen bonding in water which is even present in the frozen state of water.

Since water expands on freezing, so the volume of ice for the same mass of water is more than water. In other words, density of ice is lower than water and hence ice floats on water.


As , thus for a substance with lower density, its mass is also less.


Question 6.

Hardness of water may be temporary or permanent. Permanent hardness is due to the presence of
A. Chlorides of Ca and Mg in water

B. Sulphates of Ca and Mg in water

C. Hydrogen carbonates of Ca and Mg in water

D. Carbonates of alkali metals in water


Answer:

Permanent hardness in water is caused due to the presence of soluble salts of magnesium and calcium in the form of chlorides or sulphates in water.

So the chlorides as well as sulphates are responsible for causing permanent hardness in water.


Question 7.

Which of the following statements is correct?
A. Elements of group 15 form electron deficient hydrides.

B. All elements of group 14 form electron precise hydrides.

C. Electron precise hydrides have tetrahedral geometries.

D. Electron rich hydrides can act as Lewis acids.


Answer:

An electron-precise hydride is a type of hydride which has the exact number of electrons required to form normal covalent bonds, no excess no deficient. These are formed generally by group 14 elements like Si and C which have 4 valence electrons.

Eg. CH4 , SiH4, etc.


Due to the sp3 hybridisation configuration, the molecular geometry is tetrahedral.



sp3 hybridisation is tetrahedral in geometry.





Tetrahedral geometries of CH4 and SiCl4.


B2H6 is an electron deficient hydride. These have an incomplete octet. They are formed generally by the group 13 elements like B, Al, etc.


Question 8.

Which of the following statements is correct?
A. Hydrides of group 13 act as Lewis acid.

B. Hydrides of group 14 are electron deficient hydride.

C. Hydrides of group 14 act as Lewis acid.

D. Hydrides of group 15 act as Lewis bases.


Answer:

Electron deficient hydrides are those which have an incomplete octet. They are formed generally by the group 13 elements like B, Al, etc.

Electron rich hydrides are those which contain excess number of electrons on the central atom called lone pairs. These are formed by group 15,16,17 elements like N, O, F, etc.


Now, lewis acids are electron deficient species. They contain an empty orbital which are capable of accepting an electron pair, from Lewis base(electron enriched species) thereby forming Lewis adduct. Eg. FeCl3, FeBr3, BF3, anhydrous AlCl3, etc. Therefore we can see that hydrides of group 13 can act as Lewis acid as they are electron deficient species.


Likewise, hydrides of group 15 can act as Lewis base as they are electron rich species.


Question 9.

Which of the following statements is correct?
A. Metallic hydrides are deficient of hydrogen.

B. Metallic hydrides conduct heat and electricity.

C. Ionic hydrides do not conduct electricity in solid state.

D. Ionic hydrides are very good conductors of electricity in solid state.


Answer:

Metallic hydrides are non-stoichiometric hydrides. They conduct heat and electricity.

Whereas, ionic hydrides conduct electricity only in molten or in aqueous state. This is because charge dissociation is not possible in the solid state. It is only possible when the sample is either electrolysed or is in aqueous state.



Short Answer
Question 1.

How can production of hydrogen from water gas be increased by using water gas shift reaction?


Answer:

The water shift gas reaction is used in the formation of synthesis gas (hydrogen and carbon monoxide or carbon dioxide mixture. Here CO is converted to CO2 and H2 is also obtained from water.


Water gas is produced when super-heated steam is passed over red hot coke at very high temperature (around 1300K) in the presence of a Ni catalyst.



The H2 obtained from this reaction is difficult to obtain due to the difficulty in the removal of poisonous CO gas which is formed along. To fix this difficulty, we oxidise the poisonous CO gas to CO2 gas in another reaction where the products obtained previously is mixed with more steam over heated FeCrO4 catalyst at 673K.


Now, this obtained CO2 gas can be removed easily by passing it through sodium arsenite solution. In this way, production of H2 gas can be increased.




Question 2.

What are metallic/interstitial hydrides? How do they differ from molecular hydrides?


Answer:

Metallic hydrides -


Metallic hydrides are those compounds which are formed when transition element react with hydrogen. Eg. CaH₂ , LiBH₄


Molecular Hydrides -


Molecular hydrides are formed by the combination of an element which is having comparable higher electronegativity with hydrogen. Eg. H₂O , B₂H₆


Metal hydrides have high thermal and electrical conductivity whereas the molecular hydrides have low thermal and electrical conductivity.


Metallic hydrides are found in solid state whereas the molecular hydrides are comparatively soft & volatile.



Question 3.

Name the classes of hydrides to which H2O, B2 H6 and NaH belong.


Answer:

H2O - Electron rich hydride.


H2O is an example of electron rich hydride. It contains excess number of electrons on the central atom called lone pairs. These are formed by group 15,16,17 elements like N, O, F, etc.
B2H6 - Electron deficient hydride.


B2H6 is an electron deficient hydride. These have an incomplete octet. They are formed generally by the group 13 elements like B, Al, etc.


NaH - Ionic hydride.


Hydrides formed with alkali and alkaline-earth metals. These compounds are ionic in nature.



Question 4.

If same mass of liquid water and a piece of ice is taken, then why is the density of ice less than that of liquid water?


Answer:

Since water expands on freezing, so the volume of ice for the same mass of water is more than water. In other words, density of ice is lower than water and hence ice floats on water.


As , thus for a substance with lower density, its mass is also less.



Question 5.

Complete the following equations:

(i) PbS (s) + H2O2 (aq) →

(ii) CO (g) + 2H2 (g) →


Answer:

(i) This is an example of a redox reaction. Here, hydrogen peroxide is acting as an oxidising agent, due to which PbS (oxidation state of S is -2) is oxidised to PbSO4(oxidation state of S is +6) and H2O2(oxidation state of O is -1). itself gets reduced to H2O(oxidation state of O is -2).



(ii) This reaction yields methanol at 340K




Question 6.

Give reasons:

(i) Lakes freeze from top towards bottom.

(ii) Ice floats on water.


Answer:

(i) As we know that, , thus for a substance with lower density, its mass is also less. The density of ice is less than water. Cold water starts expanding, and becomes less dense than what it should be when temperature drops to 4°C. As a result cold water being less dense, floats on to the surface and when it comes to the chilly freezing weather conditions outside, it gets frozen.


(ii) Since water expands on freezing, so the volume of ice for the same mass of water is more than water. In other words, density of ice is lower than water and hence ice floats on water.


As , thus for a substance with lower density, its mass is also less.



Question 7.

What do you understand by the term ‘auto protolysis of water’ ? What is its significance?


Answer:

Auto protolysis of water is basically self ionisation of water. It is one of the chemical properties of water. Here, two same molecules react to give ions involving proton transfer.


This reaction also shows the amphoteric nature, which means water can act both as an acid as base.




Question 8.

Discuss briefly de-mineralisation of water by ion exchange resin.


Answer:

Demineralised water is free from all soluble mineral salts. It is obtained by passing water successively through a cation exchange and an anion exchange resin. Resins have giant molecules with -SO3H or -COOH groups.


First, the hard water is passed through the cation exchanger, which removes cations like Na+, Mg2+, Ca2+,etc. by exchanging them with H+ ions.



Now, this water coming out from cation exchanger is acidic, therefore it is passed through the anionic exchanger which removes anions like OH-, NO3-, etc. by exchanging with OH- ions.



At the end, the H+ and OH- thus produced, combine amongst themselves to produce water



This is demineralisation of water by ion exchange resin.



Question 9.

Molecular hydrides are classified as electron deficient, electron precise and electron rich compounds. Explain each type with two examples.

Explain each type with two examples.


Answer:

Molecular hydrides are classified into electron deficient, electron precise and electron rich compounds.


B2H6 is an electron deficient hydride. These have an incomplete octet. They are formed generally by the group 13 elements like B, Al, etc.



Structure of B2H6


An electron-precise hydride is a type of hydride which has the exact number of electrons required to form normal covalent bonds, no excess no deficient. These are formed generally by group 14 elements like Si and C which have 4 valence electrons.


Eg. CH4 , SiH4, etc.



Structure of CH4


NH3, H2O are examples of electron rich hydrides. These contain excess number of electrons on the central atom called lone pairs. These are formed by group 15,16,17 elements like N, O, F, etc.



Structures of NH3 and H2O



Question 10.

How is heavy water prepared? Compare its physical properties with those of ordinary water.


Answer:

Heavy water, which is deuterium oxide (D2O) is mainly prepared by electrolysis of ordinary water.


This method involves multistage electrolysis of ordinary water containing alkali like NaOH. The cylindrical vessels made of steel which act as cathode and cylindrical sheets of nickel acts as anode having a number of holes punched in it. The electrolysis carried out in different stages as we mentioned earlier. Large number of electrolytic cell are also used for this process.




Question 11.

Write one chemical reaction for the preparation of D2O2


Answer:

When D2SO4 reacts with BaO2, D2O2 is formed along with barium sulphate (BaSO4).




Question 12.

Calculate the strength of 5 volume H2O2 solution.


Answer:

We know, molar mass of H2O2 is 34gm. According to this reaction, 2 moles of peroxide is involved, so mass becomes 68gm.


Also, we know that 1mole of any gas occupies a volume of 22.4L at NTP.


Now, 5 volume H2O2 solution means that 1 L of 5 volume H2O2 on decomposition gives 5L of O2 at NTP.



So we can see from the reaction that, from 22.4L at NTP, we get 68gm H2O2.


Now to get the required 5L of O2 at NTP, we need () gm H2O2


= 15.179gm


But we know that 5L of O2 at NTP is produced from 1L of 5 volume H2O2 , as we have to find strength of 5 volume H2O2


∴ Strength of H2O2 in 5 volumes of it is 15.179gm/L


∴ Percentage strength = ()%


= 1.518%



Question 13.

(i) Draw the gas phase and solid phase structure of H2O2.

(ii) H2O2 is a better oxidising agent than water. Explain.


Answer:

(i)


Structure of H2O2 in gas phase



Structure of H2O2 in solid phase


(ii) An oxidising agent is one which oxidises(oxidation number increases) others and itself gets reduced.


The oxidising state of the oxygen atom on H2O2 is -1 which is an intermediate state. It means that it can reduce itself to H2O where oxidation state of O is -2 . So here, H2O2 acts as an oxidising agent. This is not possible for H2O so we can say that H2O2 is a better oxidising agent than water.




Question 14.

Melting point, enthalpy of vapourisation and viscosity data of H2O and D2O is given below :


On the basis of this data explain in which of these liquids intermolecular forces are stronger?


Answer:

We know, melting point, enthalpy of vapourisation, viscosity all these physical properties depend on the intermolecular forces of attraction. From the data supplied above, we can see that all the values corresponding to the properties are higher for D2O than that of H2O. So, we can say that the intermolecular forces in D2O are stronger.



Question 15.

Dihydrogen reacts with dioxygen (O2) to form water. Write the name and formula of the product when the isotope of hydrogen which has one proton and one neutron in its nucleus is treated with oxygen. Will the reactivity of both the isotopes be the same towards oxygen? Justify your answer.


Answer:

Hydrogen has three isotopes – Protium (1H1), Deuterium (2H1), Tritium (3H1). The number of neutrons is the reason why these isotopes differ from each other in spite of having the same atomic number.


Among these isotopes, only deuterium has one proton and one neutron in its nucleus. When deuterium reacts with oxygen, deuterium oxide which is heavy water (D2O), is produced.



The D – D bond is stronger than H - H bond, therefore, H2 is more reactive than D2 towards reaction with oxygen. So, they would not have the same reactivity.



Question 16.

Explain why HCl is a gas and HF is a liquid.


Answer:

HF has high boiling point than HCl because of the reason that in HF the strength of hydrogen bond is stronger than the strength of hydrogen bond in HCl.


This happens because the electronegativity of F atom is much more than that of Cl along with that F has a much smaller size. All these factors favour the formation of strong intermolecular hydrogen bonding with F atom. Due to the formation of strong and stable hydrogen bonding, high energy is required to break the H-F bond. So the boiling point of HF is more than HCl and due to which HF is a liquid and HCl is a gas.


Note – Both HCl and HF are gases at room temperature.



Question 17.

When the first element of the periodic table is treated with dioxygen, it gives a compound whose solid state floats on its liquid state. This compound has an ability to act as an acid as well as a base. What products will be formed when this compound undergoes autoionisation?


Answer:

The first element of the periodic table is hydrogen. When hydrogen reacts with dioxygen, the product formed is water. The solid state of water is ice floats on water due to its lower density. This is because water expands on freezing, so the volume of ice for the same mass of water is more than water. In other words, density of ice is lower than water and hence ice floats on water.


Water has an amphoteric nature which means that it can act both as an acid as well as a base.


Auto protolysis or auto ionisation of water is basically self ionisation of water. It is one of the chemical properties of water. Here, two same molecules react to give ions involving proton transfer.


This reaction also shows the amphoteric nature, which means water can act both as an acid as base.




Question 18.

Rohan heard that instructions were given to the laboratory attendent to store a particular chemical i.e., keep it in the dark room, add some urea in it, and keep it away from dust. This chemical acts as an oxidising as well as a reducing agent in both acidic and alkaline media. This chemical is important for use in the pollution control treatment of domestic and industrial effluents.

(i) Write the name of this compound.

(ii) Explain why such precautions are taken for storing this chemical.


Answer:

(i) The compound told in this passage is hydrogen peroxide (H2O2). It can act both as oxidising and reducing agent in acidic and alkaline media. H2O2 is important for use in the pollution control treatment of domestic and industrial effluents.


(ii) H2O2 may undergo decomposition into H2Oif it is placed in contact with sunlight or with dust particles. So it is kept in wax lined coloured bottles.


Another measure taken to prevent dissociation is by adding small amounts of negative catalyst like urea, glycerol, etc.



Question 19.

Give reasons why hydrogen resembles alkali metals?


Answer:

Hydrogen is said to be an analogous element when its position in the periodic table is considered. This is because it shares its properties both with alkali metals as well as with halogens in the field of sharing or gaining electrons or in other words it has its electronic configuration similar to these. That is why its position in the periodic table is not justified.


The electronic configuration of hydrogen (1s1) is similar to that of alkali metals (ns1) which shows that only one electron is present in their valence shell. So if they lose that single electron, a uni-positive ion would be formed.



Question 20.

Hydrogen generally forms covalent compounds. Give reason.


Answer:

Hydrogen has only one electron in its valence shell. So it can either lose that electron to form H+ or it can gain one electron to attain the noble gas configuration of Helium. So, it can form compounds with both covalent and ionic bonds.


But, the ionisation enthalpy of H is very high and electron gain enthalpy is slightly negative. Therefore, ionic bonds are not preferred, instead H likes to form compounds with covalent bonding.



Question 21.

Why is the Ionisation enthalpy of hydrogen higher than that of sodium?


Answer:

We know, the size of H atom is much smaller than that of Na atom. Due to which electrons are situated at a distance in Na from the nucleus as compared to that of H atom. As a result nuclear attraction received by the valence electrons is much higher for H atom than Na atom. So, there would be difficulty in removing a valence electron from H atom than Na atom due to higher nuclear attraction, so more energy would be required. Thus, ionisation enthalpy of hydrogen is higher than sodium.



Question 22.

Basic principle of hydrogen economy is transportation and storage of energy in the form of liquid or gaseous hydrogen. Which property of hydrogen may be useful for this purpose? Support your answer with the chemical equation if required.


Answer:

Hydrogen is in gaseous form at room temperature and due to the bulk and leakage factors, it is difficult to transport it. So, if pressure is applied and cooling is done then the gaseous hydrogen can be converted to liquid form.


Being liquid, less consumption of volume takes place, so transportation can be done easily. Thus, the basic property of hydrogen which is useful for hydrogen economy is that it can be converted into a liquid - by cooling under high pressure.



Question 23.

What is the importance of heavy water?


Answer:

Heavy water is water that contains heavy hydrogen , also known as deuterium in place of regular hydrogen. It can also be written as D2O.


Heavy water D2O is used as a moderator in nuclear reactors and in exchange reactions for the study of reaction mechanisms. In nuclear fission reactors, the neutrons must be slowed down to ensure an effective fission chain reaction occurs. This process of slowing neutrons down is known as moderation, and the material that slows down these neutrons is known as a neutron moderator. Heavy water acts as a moderator.



Question 24.

Write the Lewis structure of hydrogen peroxide.


Answer:

In hydrogen peroxide, the peroxide bond(O-O) is present and on both ends, hydrogen is bonded covalently.





Question 25.

An acidic solution of hydrogen peroxide behaves as an oxidising as well as reducing agent. Illustrate it with the help of a chemical equation.


Answer:

An oxidising agent is one which oxidises(oxidation number increases) others and itself gets reduced. Whereas a reducing agent reduces (oxidation number decreases) others and itself gets oxidised.


The oxidising state of the oxygen atom on H2O2 is -1 which is an intermediate state. It means that it can either reduce itself to H2O where oxidation state of O is -2 or it can oxidise itself to O2, where the oxidation state of O is 0.



So, we can see that H2O2 acts as an oxidising agent in the first reaction as it increases the oxidation number of I- in HI from -1 to 0 in I2.


Similarly, H2O2 acts as a reducing agent in the second reaction as it decreases the oxidation number of Cl+ in HOCl from +1 to -1 in Cl-.



Question 26.

With the help of suitable examples, explain the property of H2O2 that is responsible for its bleaching action?


Answer:

H2O2 or hydrogen peroxide acts as a strong oxidizing agent both in acidic and basic media. It acts as a bleaching agent due to the release of nascent oxygen.The nascent oxygen combines with colouring matter breaks the chemical bonds present, which in turn gets oxidised. Hence, the visible light is not absorbed and the cloth gets whitened.


Question 27.

Why is water molecule polar?


Answer:

A polar molecule is a molecule that has a slight δ positive and a slight δ negative charge distribution. Due to the high electronegativity difference between oxygen and hydrogen atoms, polarity in a molecule arises.


Question 28.

Why does water show high boiling point as compared to hydrogen sulphide? Give reasons for your answer.


Answer:

This is due to the formation of very stable intermolecular hydrogen bonding(bonding with other molecules of the same or different species) because of the presence of electronegative elements like oxygen, fluorine, nitrogen.


We know, the electronegativity of oxygen is much more than sulphur atom. So, it is expected that we would find intermolecular hydrogen bonding in water than hydrogen sulphide.


So, due to intermolecular hydrogen bonding, many similar molecules join due to the formation of these strong bonds. As a result of which, a large amount of energy is required to break these bonds. Therefore, boiling point of water is higher than that of hydrogen sulphide.



Question 29.

Why can dilute solutions of hydrogen peroxide not be concentrated by heating. How can a concentrated solution of hydrogen peroxide be obtained?


Answer:

The dilute solutions of hydrogen peroxide cannot be concentrated by simple heating. This is because hydrogen peroxide readily decomposes below its boiling point.So, to obtain a concentrated solution of hydrogen peroxide, the following steps are needed to done – •The diluted solution is carefully heated on a water bath. Doing slow evaporation, helps the release of water molecules and we obtain 50% solution of H2O2.•The 50% solution is placed in vacuum desiccator over concentrated sulphuric acid. The dehydrating nature of sulphuric acid absorbs water vapours and we get 90% solution of H2O2. •The 90% solution of H2O2 is then subjected to distillation under reduced pressure. Water distils over at 303 – 313 K and we get 99% pure H2O2 solution.


•The 99% solution of H2O2 is cooled in a freezing mixture of solid carbon dioxide and ether. As a result, crystals of hydrogen peroxide separate out which are removed. This gives completely pure hydrogen peroxide.

Question 30.

Why is hydrogen peroxide stored in wax lined bottles?


Answer:

H2O2 may undergo decomposition into H2Oif it is placed in contact with sunlight or with dust particles. So it is kept in wax lined coloured bottles.


Question 31.

Why does hard water not form lather with soap?


Answer:

As we know, soaps are cleaning agents. They are usually made by reacting alkali (eg. sodium hydroxide) with naturally occurring fat or fatty acids. Therefore we get salts of fatty acids.


Soaps have the general formula (RCO2)nMn+ (Where R is an alkyl, M is a metal and n is the charge of the cation). Hardness in water is caused due to the presence of soluble salts of magnesium and calcium in the form of chlorides or sulphates in water.


Lather is formed when the sodium or potassium salts dissolve in water. When soap is added to hard water, calcium and magnesium ions of hard water replaces so


dium or potassium ions in the soap and gets precipitated hence lather formation is hindered. Therefore, hard water does not form lather with soap.



Question 32.

Phosphoric acid is preferred over sulphuric acid in preparing hydrogen peroxide from peroxides. Why?


Answer:


In this reaction, sulphuric acid catalyses the decomposition of hydrogen peroxide formed. So different acids like phosphoric acid, carbonic acids are preferred where this decomposition of the produced hydrogen peroxide does not take place.




Question 33.

How will you account for 104.5° bond angle in water?


Answer:

Oxygen is sp3 hybridised in H2O molecule. Two hybrid orbitals are occupied by lone pairs and two are used in sigma bonding with hydrogen atoms. Now, the expected tetrahedral angle is 109.5° but the actual bond angle observed is 104.5°. This because from VSEPR theory, we know that lone pair-lone pair repulsions are greater than bond pair-bond pair repulsions and the same situation we observe here. As a result, bond angle in water is 104.5°.




Question 34.

Write redox reaction between fluorine and water.


Answer:


This is the oxidation reaction as electrons are released.



This is the reduction reaction as electrons are consumed.


Now, adding both the reactions, we get




So we can see that oxidation and reduction taking place simultaneously.



Question 35.

Write two reactions to explain amphoteric nature of water.


Answer:

Auto protolysis of water is basically self ionisation of water. It is one of the chemical properties of water. Here, two same molecules react to give ions involving proton transfer.


This reaction also shows the amphoteric nature, which means water can act both as an acid as base.



(i) Water acting as an acid



Here, water acts as Bronsted acid and donates protons.


(ii) Water acting as a base



Here, water acts as Bronsted base and accepts protons.




Matching Type
Question 1.

Correlate the items listed in Column I with those listed in Column II. Find out as many correlations as you can.



Answer:




Question 2.

Match Column I with Column II for the given properties/applications mentioned therein.



Answer:




Question 3.

Match the terms in Column I with the relevant item in Column II.



Answer:




Question 4.

Match the items in Column I with the relevant item in Column II.



Answer:





Assertion And Reason
Question 1.

In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the options given below each question.

Assertion (A) : Permanent hardness of water is removed by treatment with washing soda.

Reason (R) : Washing soda reacts with soluble magnesium and calcium sulphate to form insoluble carbonates.

(i) Statements A and R both are correct and R is the correct explanation of A.

(ii) A is correct but R is not correct.

(iii) A and R both are correct but R is not the correct explanation of A.

(iv) A and R both are false.


Answer:

(i) Statements A and R both are correct and R is the correct explanation of A.


Permanent hardness of water is due to the presence of soluble salts of magnesium and calcium in the form of chlorides and sulphates in water.


Permanent hardness can be removed by treatment of water with washing soda which contains sodium carbonate. Washing soda reacts with soluble calcium and magnesium chlorides and sulphates in hard water to form insoluble carbonates.




Question 2.

In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the options given below each question.

Assertion (A) : Some metals like platinum and palladium, can be used as storage media for hydrogen.

Reason (R) : Platinum and palladium can absorb large volumes of hydrogen.

(i) Statements A and R both are correct and R is the correct explanation of A.

(ii) A is correct but R is not correct.

(iii) A and R both are correct but R is not the correct explanation of A.

(iv) A and R both are false.


Answer:

(i) Statements A and R both are correct and R is the correct explanation of A.


Some metals like platinum and palladium can be used as storage media for hydrogen as they will not react with the atomic hydrogen due to their inertness.


They absorb large volumes of hydrogen as they have high surface area which allows hydrogen to get adsorbed over their surface.


These properties are utilized in many chemical reactions where hydrogen adsorbed over Pt or Pd is used as a catalyst.




Long Answer
Question 1.

Atomic hydrogen combines with almost all elements but molecular hydrogen does not. Explain


Answer:

Atomic hydrogen is very reactive whereas molecular hydrogen is stable. This can be understood by the dissociation enthalpy of H2 which is very high (435.88 kJ mol–1).


So, from the dissociation enthalpy of H-H bond it is clear that H2 bond will not easily break and it is relatively inert at room temperature. Thus it will only combine with few elements.


On the other hand atomic hydrogen being a single species can combine with other elements easily at room temperature.



Question 2.

How can D2O be prepared from water? Mention the physical properties in which D2O differs from H2O. Give at least three reactions of D2O showing the exchange of hydrogen with deuterium.


Answer:

D2O can be prepared by exhaustive or prolonged electrolysis of water or as a by-product in some fertilizer industries.


Some of the physical properties in which D2O differs from H2O are



Reactions of D2O showing the exchange of hydrogen with deuterium are


HCl + D2O → HOD + DCl


NaOH + D2O → NaOD + HOD


NH4Cl + D2O → NH3DCl + HOD



Question 3.

How will you concentrate H2O2? Show differences between structures of H2O2 and H2O by drawing their spatial structures. Also mention three important uses of H2O2.


Answer:

H2O2 is concentrated by distillation under reduced pressure. It can be further concentrated by careful distillation under low pressure.


H2O2 has a non polar structure whereas H2O has a polar structure which can be drawn as given below-




3 important uses of H2O are-


1. It is often used in bleach for hair and it is also used as an antiseptic and is old in market as perhydrol.


2. It is used to manufacture chemicals like sodium perborate and per-carbonate, which are present in high quality detergents.


3. It is used in industry as a bleaching agent for textiles, paper pulp, leather, etc.



Question 4.

(i) Give a method for the manufacture of hydrogen peroxide and explain the reactions involved therein.

(ii) Illustrate oxidising, reducing and acidic properties of hydrogen peroxide with equations.


Answer:

(i)It can be prepared by acidification of barium peroxide which is done by adding H2SO4. The excess water molecules then produced are evaporated under reduced pressure. The reaction for which is as follows-


BaO.8H2O (s) + H2SO4 (aq) → BaSO4(s) + H2O2 (aq) + 8H2O (l)


H2O2 acts as an oxidizing as well as reducing agent in both acidic and alkaline medium. This can be illustrated by following examples-


A. Oxidizing action in acidic medium-


2Fe2+ + 2H+ + H2O2 → 2Fe3+ + 2H2O


B. reducing agent in acidic medium-


2MnO4- + 6H+ + 5H2O2 → 2Mn2+ + 8H2O + 5O2


C. oxidizing agent in basic medium-


2Fe2+ + H2O2 → 2Fe3+ + 2OH-


D. reducing agent in basic medium-


I2 + H2O2 + OH-→ 2I- +2H2O + O2


(ii) Acidic property of Hydrogen peroxide-


It turns blue litmus red but its dilute solution is almost neutral to litmus which means it is a weak acid.


Its acidic nature can be further supported by its reaction with NaOH (base).


NaOH + H2O2 → NaHO2 + 2H2O


Since, H2O2 is a weak acid therefore CO2 is not produced as final product.



Question 5.

What mass of hydrogen peroxide will be present in 2 litres of a 5 molar solution? Calculate the mass of oxygen which will be liberated by the decomposition of 200 mL of this solution.


Answer:

Given, V = 2L and Molarity = 5M


We know that Molar mass of H2O2 = 34g


Molarity (M) =


=


5 =


W= 340g


Therefore, mass of hydrogen peroxide will be present in 2 litres of a 5 molar solution is 340g.


Mass of oxygen which will be liberated by the decomposition of 200 mL of this solution can be calculated as shown below.


No. of moles =


Molar volume = volume at STP = 22.4 L or 22400ml


No. of moles = = 0.0089


2H2O2 → 2H2O + O2


From the above equation it is clear that,


2 moles of H2O2 → 1 mole of O2


0.0089 moles of H2O2 moles of O2


Now, we know mass = no. of moles of O2 × molecular mass of O2


= = 0.15g


Mass of oxygen which will be liberated by the decomposition of 200 mL of this solution is 0.15g.



Question 6.

A colourless liquid ‘A’ contains H and O elements only. It decomposes slowly on exposure to light. It is stabilised by mixing urea to store in the presence of light.

(i) Suggest possible structure of A.

(ii) Write chemical equations for its decomposition reaction in light.


Answer:

‘A’ is Hydrogen peroxide i.e. H2O2.


Hydrogen peroxide contains H and O elements only. It decomposes slowly on exposure of light whose equation is as follows- 2H2O2 (l)→ 2H2O (l) + O2 (g)


And that’s why it is stored in wax-lined glass or plastic vessels in dark or urea can be added as a stabilizer.


(i) Possible structure of hydrogen peroxide is



(ii) Chemical equations for its decomposition reaction in light is as follows-


2H2O2 (l)→ 2H2O (l) + O2 (g)



Question 7.

An ionic hydride of an alkali metal has significant covalent character and is almost unreactive towards oxygen and chlorine. This is used in the synthesis of other useful hydrides. Write the formula of this hydride. Write its reaction with Al2Cl6.


Answer:

The ionic hydride of an alkali metal which has a significant covalent character and is almost unreactive towards oxygen and chlorine at moderate temperatures is Lithium hydride (LiH).


It is therefore used in synthesis of other useful hydrides.


Reaction of LiH with Al2Cl6 is- 8LiH + Al2Cl6→ 2LiAlH4 + 6LiCl


In this way LiH was useful in preparation of LiAlH4 which is an important hydride (often used as reducing agent in many organic reactions).



Question 8.

Sodium forms a crystalline ionic solid with dihydrogen. The solid is non-volatile and non- conducting in nature. It reacts violently with water to produce dihydrogen gas. Write the formula of this compound and its reaction with water. What will happen on electrolysis of the melt of this solid?


Answer:

The ionic solid crystal which is formed is non-volatile and non- conducting in nature. It reacts violently with water to produce dihydrogen gas.


The formula of this compound is NaH and its reaction with water is given below


NaH (s) + H2O (aq) →NaOH (aq) +H2 (g)


On electrolysis of the melt of this solid, following reaction will take place-


2H- (melt) → H2 (g) + 2e-


The melt is able to conduct electricity and liberate Dihydrogen gas at anode on electrolysis.