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Probability

Class 10th Mathematics KC Sinha Solution
Exercise 15
  1. Which of the following have ‘equally likely’ outcomes? Explain. (i) A player…
  2. Which of the following experiments have equally likely outcomes? Explain (i) A…
  3. Which of the following amongst the given options cannot be the probability of…
  4. Which of the following cannot be the probability of an event? (i) 2/3 (ii)…
  5. Find the probability of getting a head when a coin is tossed once. Also, find…
  6. Why is tossing a coin considered to be a fair way of deciding which team should…
  7. In a simultaneous throw of two coins, find the probability of getting (i) two…
  8. A bag contains a red ball, a blue ball and a yellow ball, all the balls being…
  9. Suppose we throw a die once. (i) What is the probability of getting a number…
  10. One card is drawn from a well-shuffled deck of 52 cards. Calculate the…
  11. In a throw of a fair die, find the probability of getting (i) the number 5 (ii)…
  12. A bag contains blue coloured balls only. Rahul takes out one ball without…
  13. Find the probability that a number selected from the numbers 1 to 25 is not a…
  14. A box contains 20 cards, numbered from 1 to 20. A card is drawn from the box…
  15. The numbers on the six faces of a die are replaced by the letters given below:…
  16. In a single throw of two dice, find the probability of getting the sum of…
  17. Two dice are rolled together. Write all the possible outcomes and find the…
  18. The integers from 1 to 30 are written on chits of paper (one number on each…
  19. Prakash draws a card from a well-shuffled deck of 52 cards. What is the…
  20. There are 40 students in class X of a school of whom 25 are girls, and 15 are…
  21. A bag contains 3 red balls and 5 black balls. A ball is drawn at random from…
  22. A bag contains lemon flavoured candies only. Malini takes out one candy…
  23. Two dice, one blue and one grey, are thrown at the same time. Write down all…
  24. (i) a king of red colour (ii) a face card (iii) a red face card (iv) the jack…
  25. (i) a king of red colour (ii) a face card (iii) a red face card (iv) the jack…
  26. Five cards the ten, jack, queen, king and ace of diamonds, are well-shuffled…
  27. Find the probability of a non-leap year having 53 Sundays.
  28. Shoaid tosses two coins of denominations Re 1 and 2 simultaneously. What is…
  29. A box contains 19 balls bearing numbers 1,2,3,…., 19. A ball is drawn at…
  30. A bag contains 4 white ball, 6 red balls, 7 black balls and 3 blue balls. One…
  31. A bag contains 8 red,6 white and 4 black balls. A ball is drawn at random from…
  32. A game of chance consists of spinning an arrow which comes to rest pointing at…
  33. A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn…
  34. A die is numbered in such a way that its faces show the numbers 1,2,2,3,3,6.…
  35. Cards marked with numbers 13,14,15,…, 60 are placed in a box and mixed…
  36. A bag contains 5 red balls and some blue balls. If the probability of drawing…
  37. A bag contains 5 red balls and some blue balls. If the probability of drawing…
  38. A box contains 3 blue, 2 white and 4 red marbles. If a marble is drawn at…
  39. Gopi buys a fish from a shop for his aquarium. The shopkeeper takes out one…
  40. A carton consists of 100 shirts of which 88 are good, 8 have minor defects,…
  41. (i) There are 30 cards of the same size, in a bag on which numbers 1 to 30 are…
  42. Three coins are tossed together. Find the probability of getting (i) exactly…
  43. A bag contains 20 balls numbered 1 to 20. One ball is drawn at random. Find…
  44. Two terms, A and B, play a game of football. It is known that the probability…
  45. Harpreet tosses two different coins simultaneously (say, one is of Re 1 and…
  46. Savita and Hamida are friends. What is the probability that both will have (i)…
  47. A card is drawn at random from a well-shuffled deck of playing cards. Find the…
  48. A die is thrown twice. What is the probability that (i) 5 will not come up…
  49. A game consists of tossing a one rupee coin 3 times and noting its outcome…
  50. A lot consists of 144 ball pens of which 20 are defective, and the others are…
  51. in a game of musical chairs, the person playing music has been advised to stop…
  52. A dart is thrown at a circular board which has regions marked for scoring. If…
  53. Suppose you drop a die at random on the rectangular region shown in the…
Exercise 15
Question 1.

Which of the following have ‘equally likely’ outcomes? Explain.

(i) A player calls for a head in a toss of a coin. The coin shows up either heads or tails.

(ii) Mr Sharma has one child. The child is either a boy or a girl.

(iii) An attempt was made to answer a true-false question. The answer is correct or incorrect.

(iv) A batsman plays and misses a ball. The ball either hits the wickets or misses them.
Answer:

(i) Equally likely outcome: When all the outcomes in sample space have the same probability, outcomes are called equally likely outcomes.


In a toss of a coin occurrence of head or tail have equal probabilities. Thus it has an equally likely outcome of head and tail


(ii) Equally likely outcome: When all the outcomes in sample space have the same probability, outcomes are called equally likely outcomes.


Birth of a boy or a girl has an equal probability. Now Mr Sharma has one child. The child is a boy, or a girl has an equal probability and hence it is an equally likely outcome.


(iii) Equally likely outcome: When all the outcomes in sample space have the same probability, outcomes are called equally likely outcomes.


For a true false question there are only two probabilities: True or False. Now the sample space of the attempt contains two possibilities True or False.


There can be only one correct answer for the event. Hence there is equal possibilities of answer being correct or incorrect and therefore it is an equally likely outcome.


(iv) Equally likely outcome: When all the outcomes in sample space have the same probability, outcomes are called equally likely outcomes.


A player plays a ball and misses it. Now there are many possibilities of the path took bby ball after being missed by batsman. Hence occurrence of ball hitting wicket is not an equally likely outcome with missing. As it may go to wicketkeeper or it may go pass wicket keeper. Thus there are many possibilities for the event.
Question 2.

Which of the following experiments have equally likely outcomes? Explain

(i) A driver attempts to start a car. The car starts or does not start.

(ii) A player attempts to shoot a basketball. She/he shoots or misses the shot.
Answer:

(i) Equally Likely Event:- Events that have same theoretical probability.


it's not equally likely Event as the car may have a mechanical breakdown or fuel problems or may be can be loose. So it depends upon a various thing, so it is not an equally likely event.


(ii) it is not equally likely. If he shoots the basket the ball will drop inside the basket, or he will miss it, this depends upon the skill of the individual basket ball player.
Question 3.

Which of the following amongst the given options cannot be the probability of an event:

(i) 1.01 (ii) 67%

(iii) -0.5 (iv)

(v) 0.3
Answer:

we know that 0<P(Event)<1.


we know that the probability of any event varies between 0 to 1 and cannot be negative.


(i) greater than 1 so it cannot be possible.


(ii) Since 67% = = 0.67 possible


(iii) it cannot be negative.


(iv) It is within the range, so possible


(v) It is within the range, so possible


So (i) and (iii)
Question 4.

Which of the following cannot be the probability of an event?

(i) (ii) -1.5

(iii) 15% (iv) 0.7
Answer:

we know that probability of any event varies between 0 to 1 and cannot be negative. Since 15% = =0 .15


Therefore, only option is (ii)
Question 5.

Find the probability of getting a head when a coin is tossed once. Also, find the probability of getting a tail.
Answer:

when an unbiased coin is tossed the probability of getting g a head or tail are equally likely since an unbiased coin has only HEAD or TAIL as favourable outcomes.

total number of outcomes =2


P(H) =


So, P(T) =



Question 6.

Why is tossing a coin considered to be a fair way of deciding which team should get the ball at the beginning of a football game?
Answer:

when an unbiased coin is tossed the chances of getting a head or tail are equally likely. So both teams get team equal and fair chances to try their luck. So tossing a coin considered to be a fair way of deciding which team should get the ball at the beginning of a football game.
Question 7.

In a simultaneous throw of two coins, find the probability of getting

(i) two heads

(ii) exactly one head

(iii) no tail

(iv) at least one tail
Answer:

(i) Outcomes = (H,H), (H,T),(T,H),(T,T)


Total number of outcomes = 4


Two heads occurs ony once so total number of favorable outcomes = 1


P(two heads)=


(ii) Outcomes = (H,H), (H,T),(T,H),(T,T)


Total number of outcomes = 4


Exactly one head occurs 2 times so a total number of favourable outcomes = 2.


P(exactly one head) = 2/4


(iii) Outcomes = (H,H), (H,T),(T,H),(T,T)


Total number of outcomes = 4


No tails occurs only one time when there are two heads = 1


so total number of favourable outcomes = 1


P(no tails) = 1/4


(iv) Outcomes = (H,H), (H,T),(T,H),(T,T)


Total number of outcomes = 4


Atleast one tails occurs 3 times


so total number of favourable outcomes = 3


P(atleast 1 tail) = 1/4
Question 8.

A bag contains a red ball, a blue ball and a yellow ball, all the balls being of the same size. Kritika takes out a ball from the bag without looking into it. What is the probability that she takes out the

(i) yellow ball? (ii) red ball? (iii) blue ball?
Answer:

total number of balls = 3


(i)


(ii)


(iii)



Question 9.

Suppose we throw a die once.

(i) What is the probability of getting a number greater than 4?

(ii) What is the probability of getting a number less than or equal to 4?
Answer:

(i) Outcomes (X) = 1,2,3,4,5,6


In a dice throw number greater than 4 are 5,6 So


so total number of favorable outcomes = 2


So P(X>4) =


(ii) Outcomes (X) = 1,2,3,4,5,6


Number less than or equal to 4 are 1,2,3,4


so total number of favorable outcomes = 4


P(X) =



Question 10.

One card is drawn from a well-shuffled deck of 52 cards. Calculate the probability that the card will

(i) be an ace,

(ii) not be an ace
Answer:

There are 4 suits in a pack of 52 cards


13- Heart


13- Diamond


13- Spades


13- Clubs


Each suit has one ace, 1jack, 1king, 1queen


So total ace cards = 4


(i) The probability of getting an Ace =


(ii) There are 48 cards which are not ace


The probability of not getting an Ace =



Question 11.

In a throw of a fair die, find the probability of getting

(i) the number 5

(ii) the number 3 or 4

(iii) a prime number

(iv) a number greater than 4

(v) a number greater than 6

(vi) a number less than 6
Answer:

Outcomes (X) = 1,2,3,4,5,6


(i)The number 5 appers only once in a throw of dice So P(X)=


(ii) There are either chances of getting 3 or 4 P(X) =


(iii)Prime Number:- a number which is divisible by 1 or number itself.


So favourable cases are 2,3,5 P(X)=


(iv)Number greater than 4 are 5,6 so P(X)=


(v) A Dice contains only n1,2,3,4,5,6 as the number, so there is no chance of getting a number than 6 So P(X)=0


(vi) Since A Dice contains only n1,2,3,4,5,6 as the number So Number, less than 6 is P(X)=



Question 12.

A bag contains blue coloured balls only. Rahul takes out one ball without looking into the bag. What is the probability of his

(i) taking out a green ball?

(ii) taking out a blue ball?
Answer:

(i) 0 Since there are only blue balls so taking, green balls will be zero.


(ii)1 Since there are only blue balls.
Question 13.

Find the probability that a number selected from the numbers 1 to 25 is not a prime number when each of the given numbers is equally likely to be selected.
Answer:

Outcomes= 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25


Prime Numbers = 2,3,5,7,11,13,17,19,23


Let x be the event of getting prime numbers


P(x)=


Therefore the probability of getting non-prime number =



Question 14.

A box contains 20 cards, numbered from 1 to 20. A card is drawn from the box at random. Find the probability that the number on the card drawn is (i) even (ii) prime and (iii) multiple of 3
Answer:

Even number = 2,4,6,8,10,12,14,16,18,20


Prime Number = 2,3,5,7,11,13,17,19


Multiple of 3 = 3,6,9,12,15,18


(i)Probability of getting an Even Number =


(ii)Probability of getting a prime number =


(iii)Probability of getting a multiple of 3 =



Question 15.

The numbers on the six faces of a die are replaced by the letters given below:



In the throw of this die, find the probability of getting

(i) A (ii) B
Answer:

(i) Sample Space = (A, A, B, C, D, E)


Number of A’s = 2


Probability of getting an A =


(ii) Sample Space = (A, A, B, C, D, E)


Numbher of B’s = 1


Probability of getting a B =



Question 16.

In a single throw of two dice, find the probability of getting the sum of numbers appearing on the two dice.

(i) greater than 8

(ii) Less than or equal to 12

(iii) equal to 7

(iv) divisible by 3 or 4
Answer:

Outcomes= (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)


(2,1)(2,2),(2,3),(2,4),(2,5),(2,6)


(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)


(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)


(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)


(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)


(i) (6,3),(6,4),(6,5),(6,6),(3,6),(4,5),(4,6),(5,4),(5,5),(5,6)


P (sum greater than 8) =


(ii) Less than or equal to 12 = ?


Outcomes = All Outcomes have sum less than or equal to 12.


P (sum Less than or equal to 12) = 36/36 = 1


(iii) Sum equal to 7


Outcomes = (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1) = 6


P (sum equal to 7) =


(iv) Divisible by 3 or 4


Outcomes =


(1,2),(1,3),(1,5),(2,1)(2,2),(2,4),(2,6),(3,1),(3,3),(3,5),(3,6),(4,2),(4,4),(4,5),(5,1),(5,3),(5,4),(6,2),(6,3),(6,6)


P(divisible by 3 or 4)=



Question 17.

Two dice are rolled together. Write all the possible outcomes and find the probability of getting

(i) a number greater than 4 on each die.

(ii) a doubtlet (the same number appearing on each of the die)
Answer:

(i) (5,5),(5,6),(6,5),(6,6)


P(a number greater than 4 on each die) =


(ii) (1,1),(2,2),(3,3),(4,4),(5,5),(6,6)


P(a doubtlet (the same number appearing on each of the die)) =



Question 18.

The integers from 1 to 30 are written on chits of paper (one number on each chit). These chits are then put in a box and well mixed. Ramesh picks up one chit. What is the probability that his chit has

(i) the number 5

(ii) an odd number

(iii) a prime number
Answer:

(i) P(the number 5) =


(ii) 1,3,5,7,9,11,13,15,17,19,21,23,25,27,29


P(an odd number) =


(iii) 2,3,5,7,11,13,17,19,23,29


P(a prime number) =



Question 19.

Prakash draws a card from a well-shuffled deck of 52 cards. What is the probability that he draws

(i) a king (ii) a red card (iii) a diamond (iv) the six of spade
Answer:

There are 4 suits in a pack of 52 cards


13- Heart


13- Diamond


13- Spades


13- Clubs


Each suits has 1 ace , 1jack, 1king , 1queen


26- red card , 26- black card


(i) P(a king) =


(ii) P(a red card ) =


(iii) P(a diamond) =


(iv) P(the six of spade) =



Question 20.

There are 40 students in class X of a school of whom 25 are girls, and 15 are boys. The class teacher has to select one student as a class representative. She writes the name of each student on a separate card, the cards being identical. Then she puts the cards in a bag and mixes them thoroughly. She then draws one card from the bag. What is the probability that the name is written on the card is the name of

(i) a girl? (ii) a boy?
Answer:

Sample Space = 40


Number of Girls = 25


Number of Boys = 15


(i) P(a girl) =


(ii) P(a boy) =



Question 21.

A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red? (ii) not red?
Answer:

Total number of balls :- 8


Red Balls = 3


Not Red Balls = 5


(i) P (red) =


(ii) P(not red)=



Question 22.

A bag contains lemon flavoured candies only. Malini takes out one candy without looking into the bag. What is the probability that she takes out

(i) an orange flavoured candy?

(ii) a lemon flavoured candy?
Answer:

since there are only lemon coloured candies therefore


(i) P(an orange flavoured candy) = 0


(ii) P(a lemon flavoured candy) = 1
Question 23.

Two dice, one blue and one grey, are thrown at the same time. Write down all the possible outcomes. What is the probability that sum of the two numbers appearing on the top of the dice is

(i) 8 (ii) 13 (iii) less than or equal to 12?
Answer:

Outcomes= (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)


(2,1)(2,2),(2,3),(2,4),(2,5),(2,6)


(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)


(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)


(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)


(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)


(i)Sum is 8


Favourable outcomes = (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) = 5


P(sum is 8) =


(ii)Sum is 13


Favourable Outcomes = 0


P(sum is 13) = 0


Since the maximum sum that can be obtained is 12.


(iii) Less than or equal to 12


Possible outcomes = All outcomes have sum less than or equal to 7.


P(less than or equal to 12) = 1
Question 24.

In a deck of card. Find the probability of getting

(i) a king of red colour

(ii) a face card

(iii) a red face card

(iv) the jack of hearts

(v) a spade

(vi) the queen of diamonds
Answer:

There are 4 suits in a pack of 52 cards


13- Heart


13- Diamond


13- Spades


13- Clubs


Each suits has 1 ace , 1jack, 1king , 1queen


Face Cards are Jack, king ,queen. So there are 3 face cards.


Total number of face cards =12


26- red card , 26- black card


(i) Since There are 26 red Cards and a total of 2 kings are there.


So P(a king of red colour) =


(ii) Total number of face cards = 12


So P(a face card) =


(iii) Total number of red cards =26


Total number of red face cards = 6


P(a red face card) =


(iv) P(a jack of heart) =


(v) P(a spade) =


(vi) P(a queen of diamond) =



Question 25.

In a deck of card. Find the probability of getting

(i) a king of red colour

(ii) a face card

(iii) a red face card

(iv) the jack of hearts

(v) a spade

(vi) the queen of diamonds
Answer:

There are 4 suits in a pack of 52 cards


13- Heart


13- Diamond


13- Spades


13- Clubs


Each suits has 1 ace , 1jack, 1king , 1queen


Face Cards are Jack, king ,queen. So there are 3 face cards.


Total number of face cards =12


26- red card , 26- black card


(i) Since There are 26 red Cards and a total of 2 kings are there.


So P(a king of red colour) =


(ii) Total number of face cards = 12


So P(a face card) =


(iii) Total number of red cards =26


Total number of red face cards = 6


P(a red face card) =


(iv) P(a jack of heart) =


(v) P(a spade) =


(vi) P(a queen of diamond) =



Question 26.

Five cards the ten, jack, queen, king and ace of diamonds, are well-shuffled with their face downwards. One card is then picked up at random.

(i) What is the probability that the card is the queen?

(ii) If the queen is drawn and put aside, what is the probability that the second card picked up is

(a) an ace? (b) a queen?
Answer:

Total number of cards:- 5

(i) P(probability that the card is the queen) =


Now, Total number of cards = 4


(ii) (a) P(an ace) =


(b) P(a queen) = 0


Since there was only one queen which is put aside.
Question 27.

Find the probability of a non-leap year having 53 Sundays.
Answer:

1 year = 365 days


And a year has 52 weeks


So 52 × 7= 364 days


So now remaining 1 day can be any day i.e. Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday


So P(probability of a non-leap year having 53 Sundays) =



Question 28.

Shoaid tosses two coins of denominations Re 1 and 2 simultaneously. What is the probability that he get at least one head?
Answer:

Outcomes = (H,H), (H,T),(T,H),(T,T)


Atleast 1 head means that number of heads are one or more than 1.


Possible Outcomes = 3


P( that he get at least one head) =



Question 29.

A box contains 19 balls bearing numbers 1,2,3,…., 19. A ball is drawn at random from the box. Find the probability that the number on the ball is

(i) a prime number

(ii) divisible by 3 or 5

(iii) neither divisible by 5 nor by 10

(iv) an even number
Answer:

(i) Possible Outcomes: 2,3,5,7,11,13,17,19


P(a prime number) =


(ii) Possible Outcomes: 3,5,6,9,12,15,10,18


P(divisible by 3 or 5) =


(iii) Possible Outcomes: 1,2,3,4,6,7,8,9,11,12,13,14,16,17,18,19


P(neither divisible by 5 nor by 10) =


(iv) Possible Outcomes: 2,4,6,8,10,12,14,16,18


P(an even number) =



Question 30.

A bag contains 4 white ball, 6 red balls, 7 black balls and 3 blue balls. One ball is drawn at random from the bag. Find the probability that the ball drawn is

(i) white

(ii) not black

(iii) neither white nor black
Answer:

Total number of balls = 20


(i) Number of White Balls = 4


Total Balls = 20


P(white) =


(ii) No black means the we have to pick white, red, blue balls only


P(not black) =


(iii) neither black nor white means only white and red balls are left


P(neither white nor black) =



Question 31.

A bag contains 8 red,6 white and 4 black balls. A ball is drawn at random from the bag. Find the probability that the ball is drawn is :

(a) Red or white

(b) Not black

(c) Neither white Nor black
Answer:

Total number of balls :- 18


Number of black balls:- 4


Number of white balls:- 6


Number of Red balls:- 8


(a) Since there are 14 balls which are red and white colour, so the total number of favourable cases becomes = 14


Total number of balls = 18


P(Red or white) =


(b) Not black balls mean that red or white is drawn.


Total number of balls = 18


P(Not black) =


(c) Neither white nor black means that the ball is drawn are red


Total Number of favourable cases = 8


P(Neither white Nor black) =



Question 32.

A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1,2,3,4,5,6,7,8, and these are equally likely outcomes. What is the probability that it will point at

(i) 8?

(ii) an odd number?

(iii) a number greater than 2?

(iv) a number less than 9?
Answer:

(i) Number of times 8 comes = 1


P(8) =


(ii) Number of Favourable outcomes = 1, 3, 5, 7 = 4


P(an odd number) =


(iii) Number of Favourable Outcomes = 3, 4, 5, 6, 7, 8 = 6


P(a number greater than 2) =


(iv) Number of Favourable Outcomes = 1, 2, 3, 4, 5, 6, 7, 8 = 8


P(a number less than 9) = 1
Question 33.

A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that it bears (i) a two-digit number (ii) a perfect square number (iii) a number divisible by 5.
Answer:

(i) Number of two digit numbers = 90 – (1, 2, 3, 4, 5, 6, 7, 8, 9) = 81


P(a two-digit number) =


(ii) Number of perfect squares = 1, 4, 9, 16, 25, 36, 49, 64, 81 = 9


P(a perfect square number) =


(iii) Numbers divisible by 5 = 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90 = 18


P(a number divisible by 5) =



Question 34.

A die is numbered in such a way that its faces show the numbers 1,2,2,3,3,6. It is thrown two times and the total score in two throws is noted. Complete the following table which gives a few values of the total score on the two throws:

Number in first throw



What is the probability that the total score is

(i) even (ii) 6? (iii) at least 6?
Answer:

Total number of outcomes = 36


(i)Number of even score = 18


Hence, P (even score) =


(ii)Number of times 6 comes = 4


Hence, P (score of 6) =


(ii)Number of times score is 6 or more = 15


Hence, P (score at least 6) =



Question 35.

Cards marked with numbers 13,14,15,…, 60 are placed in a box and mixed thoroughly. One card is drawn at random from the box. Find the probability that number on the drawn card is

(i) divisible by 5.

(ii) a number which is a perfect square.
Answer:

(i) number divisible by 5


15,20,25,30,35,40,45,50,55,60


P(divisible by 5) =


(ii) 16,25,36,49


P(a number which is a perfect square) =



Question 36.

A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball from the bag is thrice that of a red ball, find the number of blue balls in the bag.
Answer:

Let the number of blue balls be X


So total number of balls = 5+X


P(probability of drawing a red ball from the bag) =


P(probability of drawing a blue ball from the bag)=


ATQ ,


=


=


5X +X2 = 75+15X


X2 - 10X+ -75 = 0


(x-15)(x+5) =0


So X -5


Therefore No. Of blue balls = 15
Question 37.

A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball from the bags is four times that of a red ball, find the number of blue balls in the bag.
Answer:

Let the number of blue balls be X


So total number of balls = 5 + X


P(probability of drawing a red ball from the bag) =


P(probability of drawing a blue ball from the bag)=


ATQ ,


=


=


5X +X2 = 100+20X


X2 - 15X+ -100 = 0


(x-20)(x+5) =0


So X -5


Therefore No. Of blue balls = 20
Question 38.

A box contains 3 blue, 2 white and 4 red marbles. If a marble is drawn at random from the box, what is the probability that it will be

(i) white? (ii) blue? (iii) red?
Answer:

Total Number of Marbles:- 9


White Marbles = 2


Blue Marbles = 3


Red Marbles = 4


(i)P(white) =


(ii)P(blue) =


(iii)P(red) =



Question 39.

Gopi buys a fish from a shop for his aquarium. The shopkeeper takes out one fish at random from a tank containing 5 male fish and 8 female fish. What is the probability that the fish taken out is a male fish?
Answer:

Total number of fishes = 13


P(probability that the fish are taken out is a male fish) =



Question 40.

A carton consists of 100 shirts of which 88 are good, 8 have minor defects, and 4 have major defects. Jimmy, a trader, will only accept the shirts which are good, but Sujatha, another trader, will only reject the shirts which have major defects. One shirt is drawn at random from the carton. What is the probability that

(i) it is acceptable to Jimmy?

(ii) it is acceptable to Sujatha?
Answer:

Total number of bulbs = 100


Total number of good bulbs = 88


Bulbs having minor defects = 8


Bulbs having major defects = 4


(i) it is acceptable to jimmy only it is good


P(it is acceptable to Jimmy) =


(ii) She will accept all the bulbs which do not have major defects. So, total bulbs acceptable to her is 96


P(it is acceptable to Sujatha) =



Question 41.

(i) There are 30 cards of the same size, in a bag on which numbers 1 to 30 are written. One card is taken out of the bag at random. Find the probability that the number on the selected cards is not divisible by 3.

(ii) If the probability of an event E, i.e., P (E) is 0.08, what would the probability of the event ‘not E’ be?

(iii) In a group of 3 students, the probability of 2 students not passing an examination is 0.895. Find the probability of the 2 students passing the examination.
Answer:

(i) Total number of cards = 30


Number divisible by 3 = 3,6,9,12,15,18,21,24,27,30


P(probability that the number on the selected cards is not divisible by 3) =


(ii) P(E) = 0.8


P(not E) = 1-0.08 =0.92


(iii) P (the probability of the 2 students passing the examination) = 1-0.895 = 0.105
Question 42.

Three coins are tossed together. Find the probability of getting

(i) exactly two tails

(ii) at least one head

(iii) at least one head and one tail
Answer:

Total number of outcomes = (HHH),(HHT),(HTH),(THH),(TTH),(TTT),(THT),(HTT)


(i) P(exactly two tails) =


(ii) P(at least one head) =


(iii) P(at least one head and one tail) = 1
Question 43.

A bag contains 20 balls numbered 1 to 20. One ball is drawn at random. Find the probability that it is marked with a number which is a multiple of 5 or 7.
Answer:

Total Number of Balls = 20


Number of balls that are multiple of 5 and 7 are = 5, 7, 10, 14, 15, 20 = 6



P(probability that it is marked with a number which is a multiple of 5 or 7) =



Question 44.

Two terms, A and B, play a game of football. It is known that the probability of A winning the game is 0.58. What is the probability of B winning the game if a tie is ruled out?
Answer:

P(A winning the game) = 0.58


B will the game only when A loses


P(B winning the game) = 1 - 0.58


= 0.42
Question 45.

Harpreet tosses two different coins simultaneously (say, one is of Re 1 and other of Rs. 2). What is the probability that she gets at least one head?
Answer:

Outcomes = (H, H), (H,T), (T, H), (T, T)


Atleast one head means that there is one and more than one heads. And from outcomes we can see that it happens 3 times.


Total number of outcomes = 4



P(probability that she gets at least one head) =



Question 46.

Savita and Hamida are friends. What is the probability that both will have (i) different birthdays? (ii) the same birthday? (ignoring a leap year).
Answer:

Since there are 365 days


(i)If Savita is born is any day and Hamida born on any day except on which Savita was born.


P(different birthdays) =


(ii) If Savita and Hamida have a same birthday, then it can be any 1 day of 365 days.


P(the same birthday) =



Question 47.

A card is drawn at random from a well-shuffled deck of playing cards. Find the probability of drawing a

(i) face card

(ii) card which is neither a king nor a r

d card.
Answer:

There are 4 suits in a pack of 52 cards

13- Heart


13- Diamond


13- Spades


13- Clubs


Each suits has 1 ace , 1jack, 1king , 1queen


Face cards = king ,queen,jack


Total face cards = 12


(i) P (probability of drawing a face card ) =


(ii) P(probability of drawing a card which is neither a king nor a red card) =



Question 48.

A die is thrown twice. What is the probability that

(i) 5 will not come up either time?

(ii) 5 will come up at least once?

[Hint: Throwing a die twice and throwing two dice simultaneously are treated as the same experiment]
Answer:

Outcomes= (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1)(2,2),(2,3),(2,4),(2,5),(2,6)


(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)


(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)


(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)


(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)


(i) P(5 will not come up either time) =


Explanation:- 5 will not come up either time means In the throw no dice gets a number 5 on them so possible outcomes = (1,1),(1,2),(1,3),(1,4),(1,6)


(2,1)(2,2),(2,3),(2,4),(2,6)


(3,1),(3,2),(3,3),(3,4),(3,6)


(4,1),(4,2),(4,3),(4,4),(4,6)


(6,1),(6,2),(6,3),(6,4),(6,6)


(ii) P(5 will come up at least once) =


Explanation:- 5 will come up at least once means either of the dice gets a number 5 on them. So possible outcomes are :- (1,5),(2,5),(3,5),(4,5),(6,5) (5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
Question 49.

A game consists of tossing a one rupee coin 3 times and noting its outcome each time. Hanif wins if all the tosses give the same result, i.e., three heads or three tails, and loses otherwise. Calculate the probability that Hanif will lose the game.
Answer:

Total number of outcomes = (HHH),(HHT),(HTH),(THH),(TTH),(TTT),(THT),(HTT)


Given: Hanif loses if there are different coins = 8 – 2 = 6


For Hanif to lose the game, there are 6 possible chances


P(probability that Hanif will lose the game) =



Question 50.

A lot consists of 144 ball pens of which 20 are defective, and the others are good. Nuri will buy a pen if it is good, but will not buy if it is defective. The shopkeeper draws one pen at random and gives it to her. What is the probability that

(i) She will but it?

(ii) She will not buy it?
Answer:

(i) P(probability She will buy it) =?


Sample Space = 144 ball pens


Good Pens = 144 – 20 = 124


Defective Pens = 20




(ii) P(She will not buy it) =?


Sample Space = 144 ball pens


Good Pens = 144 – 20 = 124


Defective Pens = 20
Question 51.

in a game of musical chairs, the person playing music has been advised to stop playing the music at any time within 1 minute after she starts playing. What is the probability that the music will stop within the first 20 seconds after starting?
Answer:

Music has to be Stopped within 1 minute


1 minute = 60 seconds


Music is stopped within 20 seconds


Probability =


Probability =



Question 52.

A dart is thrown at a circular board which has regions marked for scoring. If the dart hits the region 1, the player gets 50 points and if it hits the region 2, the player gets 100 points. If the dart hits the board, find probability of the player getting 100 points.
Answer:

Area of bigger circle = 3.14×50×50


= 7850


Area of smaller circle = 3.14×20×20


=1256


Now if the player wants to score 100 points in a single shot then he will have to hit inside the smaller circle


So P(scoring 100) =



Question 53.

Suppose you drop a die at random on the rectangular region shown in the figure. What is the probability that it will land inside the circle with diameter 1 m?
Answer:


Length = 3m


Breadth = 2m


Area of Rectangle :- L × B


= 6m2


Area of circle = πr2


Radius = .


Area = .25πm2


P(it will land inside the circle) =


=



=


=