Data Handling

By observing the above-given marks of 40 students, we can construct the table as follows:

(a) Students who have scored marks equal to and more than 7 = No. of students with marks 7 +No. of students with marks 8 + No. of students with marks 9
5 + 4 + 3

= 12

(b) Students who have scored marks less than 4 =No. of students with marks 1 + No. of students with marks 2 + No. of students with marks 3
2 + 3 + 3

= 8

(a) By observing the choices of given 30 students, we can construct a table as follows:

(b) From the above table, it is clear that Ladoo is the most preferred sweet as most number of students preferred the sweet ladoo

Table for the above-given data is as follows:

(a) From the above table, the number which appeared the minimum number of times is 4

(b) From the above table, the number which appeared the maximum number of times is 5

(c) From the above table, there are two numbers which appear for the same number of times and these are 1 and 6

(i) From the above pictograph, it is clear Village D has the minimum number of tractors as this village has only 3 tractors

(ii) From the above pictograph, it is clear Village C has the maximum number of tractors as this village has 8 tractors

(iii) From the above pictograph,

Number of more tractors that village C has as compared to B = 8 – 5 = 3

(iv) From the above pictograph,

Total number of tractors in all given villages = 6 + 5 + 8 + 3 + 6

= 28

From the above table, it is clear:

(a) From the above table, it is clear, class VIII has the minimum number of girls i.e. 6

(b) No, class VI has more number of girls than class V. Clearly, in class V and VI there are 10 and 16 girls respectively.

(c) From the above-given table,

In class VII there are total 12 girls

From the above-given pictograph, we can conclude following:

a) Firstly, there are following number of bulbs on different days of the week:

b) From the given pictograph and above table, we can conclude that maximum number of bulbs were sold on Sunday, i.e. 18

c) From the above-given table, equal number of bulbs were sold on Wednesday and Saturday i.e. 8

d) From the above-given table, minimum number of bulbs were sold on Wednesday and Saturday i.e. 8

e) From the above given table,

Total number of bulbs sold in a week = 12 + 16 + 8 + 10 + 14 + 8 + 18

= 86
9 bulbs can be in = 1 carton
1 bulb can be in =
86 bulbs can be in = cartons
As number of cartons cannot be in decimal.
So 10 cartons will be needed.

From the above-given pictograph following table is constructed:

(a) From the above-given table, it is clear Martin sold maximum number of baskets i.e. 950

(b) Total number of fruit baskets sold by Anwar is 700

(c) The merchants who have sold more than 600 baskets are Anwar, Martin and Ranjit. Therefore, they are planning to buy a godown for the next season

We can prepare the pictograph of the given data as follows:

(a) Here,

We know that,

⊗ = 10 animals

And, it is given that, Village E has 60 animals

Hence, 6 symbols (⊗) will represent the animals of village E

(b) We can see that,

Maximum numbers of symbols (⊗) are there in the section of village B

And,

⊗ = 10 animals

Hence, Village B has a maximum number of animals.

It has 10 × 12 = 120 animals.

(c) We can observe that,

Village A has 8 symbols (⊗)

And, Village C has 9 symbols (⊗)

Now, we know that,

⊗ = 10 animals

Therefore, Village A has 80 animals

And, Village C has 90 animals

Clearly, village C has more animals in it.

(A) We can prepare the pictograph of the given data as follows:

(a) Here,

We know that,

= 100 students

And, it is given that, In the year 2002, there were 600 students

Hence,

6 symbols will represent the students of the year 2002

(b) Here,

We know that,

= 100 students

And, it is given that, in the year 1998, there were 535 students

Hence,

5 complete and one incomplete symbol will represent the students of the year 1998.

(B)

Hence,

We can observe that,

The second pictograph is more informative

(a) We can clearly see that, the year in which there was a maximum purchase of wheat was the year 2002 with a purchase of 30 thousand tons.

(b) We can clearly see that, the year in which there was a least purchase of wheat was the year 1998 with a purchase of 15 thousand tons.

The parts of the questions are solved below:

(a) The bar graph represents the number of shirts sold from Monday to Saturday.

(b) The scale of the horizontal line representing the number of shirts is chosen as:

1 unit = 5 shirts

(c) From the given bar graph we can observe that,

The maximum shirts were sold on Saturday with a total number of 60 shirts.

(d) From the given bar graph we can observe that,

The minimum shirts were sold on Tuesday with a total number of 10 shirts.

(e) 35 shirts were sold on Thursday.

The various parts of the question are solved below:

(a) We can clearly observe that,

The given bar graph shows the marks obtained by Aziz in various subjects.

(b) The maximum marks were scored by Aziz in the subject of Hindi.

He scored 80 marks in Hindi.

(c) The least marks were scored by Aziz in the subject of Social Studies.

He scored 40 marks in Social Studies.

(d) The name of the subject with its respective marks are listed below:

Hindi = 80

English = 60

Maths = 70

Science = 50

Social studies = 40

According to the question,

We will take a scale of 1 unit length = 5 units

And hence,

We will draw the graph based on the above given data as follows:

We can clearly observe that,

The most preferred activity by the students after playing is reading story books.

According to the question,

By taking a scale of 1 unit = 10 books, a bar graph of the above-given data can be constructed as follows:

According to the question,

By taking a scale of 1 unit = 100 bicycles, a bar graph of the above-given data can be constructed as follows:

(a) We can see that,

The maximum number of bicycles were manufactured in the year 2002.

A total of 1200 bicycles were manufactured.

(b) We can see that,

The minimum number of bicycles were manufactured in the year 2001.

A total of 600 bicycles were manufactured

According to the question,

By taking a scale of 1 unit = 20 thousands, a bar graph of the above-given data can be constructed as follows:

(a) We can clearly observe that,

The age groups in which the population is same are 30 – 44 and 45 – 59.

(b) We know that,

The senior citizens are the people that are either from the age group of 60 – 74 or from the age group of 75 and above.

Hence,

We can calculate the number of senior citizens as follows:

Total no. of senior citizen = 80,000 + 40,000

= 1,20,000